A ball is thrown with a velocity of 39.2 m/s at an angle of 30° with the horizontal. Calculate the maximum height, time taken by the ball to return to the same level and the horizontal distance from the initial point to the point where the ball returns to the same level
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Answer:
.2.7 is the answer
Explanation:
because if we calculate the maximum height so answer is this
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Maximum height, = 19.6 m
time of flight = TF = 4s
Horizontal range, R = = 135.79m
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