Question

A ball is thrown with the velocity of 39.2metre per sec atcan angle 30degree with the horizontal calculate the maximum height,time of flight and horizontal range of the projectile

Answer 1

Max height=u²sin²theta/2g

Time of flight=2usintheta/g

Given u=39.2units. Take,g=9.8m/s²,theta30

Then max height=39.2*39.2*1/4÷2*9.8

=19.6 m

T=2*39.2*1/2÷9.8=4s