A ball is thrown with the velocity of 39.2metre per sec atcan angle 30degree with the horizontal calculate the maximum height,time of flight and horizontal range of the projectile
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Max height=u²sin²theta/2g
Time of flight=2usintheta/g
Given u=39.2units. Take,g=9.8m/s²,theta30
Then max height=39.2*39.2*1/4÷2*9.8
=19.6 m
T=2*39.2*1/2÷9.8=4s
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