Physics, asked by Aarav577, 1 year ago

A ball is thrown with the velocity of 39.2metre per sec atcan angle 30degree with the horizontal calculate the maximum height,time of flight and horizontal range of the projectile

Answers

Answered by Jkumar20
32

Max height=u²sin²theta/2g

Time of flight=2usintheta/g

Given u=39.2units. Take,g=9.8m/s²,theta30

Then max height=39.2*39.2*1/4÷2*9.8

=19.6 m

T=2*39.2*1/2÷9.8=4s

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