Question

a ball is thrown with velocity 20 m/s with the horizontal wih an angale 45^0 find the value of time of flight ?​

Answer 1

Given :

Initial velocity = 20 m/s

Angle of incidence = 45°

To Find :

Time of flight of the ball.

Solution :

❒ A body is said to be projectile if it is projected into space with some initial velocity and then it continues to move in a vertical plane such that its horizontal acceleration is zero and vertical downward acceleration is equal to g.

• Time of flight is defined as the time taken by projectile to come back at the ground$.$

Formula : T = 2u sin θ / g

» T denotes time of flight

» u denotes initial velocity

» g denotes acc. due to gravity

» θ denotes angle of projection

By substituting the given values;

➠ T = 2u sin θ / g

➠ T = 2 × 20 × sin 45° / 10

➠ T = 4 × 1/√2

➠ T = 2√2 s

Diagram :

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Answer 2

Answer:

Given :

Initial velocity = 20 m/s

Angle of incidence = 45°

To Find :

Time of flight of the ball.

Solution :

❒ A body is said to be projectile if it is projected into space with some initial velocity and then it continues to move in a vertical plane such that its horizontal acceleration is zero and vertical downward acceleration is equal to g.

Time of flight is defined as the time taken by projectile to come back at the ground..

Formula : T = 2u sin θ / g

» T denotes time of flight

» u denotes initial velocity

» g denotes acc. due to gravity

» θ denotes angle of projection

By substituting the given values;

➠ T = 2u sin θ / g

➠ T = 2 × 20 × sin 45° / 10

➠ T = 4 × 1/√2

➠ T = 2√2 s