Question

A ball is thrown with velocity 40 m//s at angle 30^(@) with horizontal from the top of a tower of height 60 m. At what horizontal distance from the foot of tower, the ball will strike the gorund ?

Answer 1

Answer:

120(root 3)

Explanation:

y:−60=40sin30∘t−12gt2

=20t−5t2

t2−4t−12=0⇒t=6s

x=40cos30∘t=40×$\sqrt{3}$/2×6=120$\sqrt{3}$m