A ball is thrown with velocity 8 ms-1
making an angle 60° with the horizo-
ntal. Its velocity will be perpendi-
cular to the direction of initial
velocity of projection after a time of
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let velocity of body after time t is perpendicular upon initial velocity .
velocity after time t
v = ucos∅ i + (usin∅ -gt ) j
initial velocity
v° = ucos∅ i + usin∅ j
because v and v° is perpendicular so,
v.v° = 0
{ucos∅ i + (usin∅ -gt) j }{ucos∅ i + usin∅ j } =0
u²cos²∅ +u²sin²∅ -usin∅.gt =0
u - sin∅gt = 0
t = u/sin∅g
=8/sin60.10
=8/√3/210
=1.6√3 sec
t = 1.6√3 sec
Explanation:
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