a ball is thrown with velocity of 39.2 m/s at an angle 30° with the horizontal.Calculate the maximum height,time of flight and horizontal range of the projectile
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,v=√2gh..
then
v^2= 2×9.8×h..
(39.2)^2= h×19.6
then
v^2= 2×9.8×h..
(39.2)^2= h×19.6
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