Math, asked by amonbhatti3881, 11 hours ago

A ball is tossed to a height of 4 meters rebounds to 40% of its previous height. Find the distance the ball has travelled when it strikes the ground for the fifth time.

Answers

Answered by sehrawatrajesh1978
0

Answer:

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Answered by ramnareshpandey8888
0

Answer:

40% of its previous height until it stops.

Step-by-step explanation:

Toss up 4m

1st drop 4m

1st rebound 4(0.4)

2nd drop 4(0.4)

2nd rebound 4(0.4)^2

3rd drop 4(0.4)^2

3rd rebound 4(0.4)^3

4th drop 4(0.4)^3

4th rebound 4(0.4)^4

5th drop 4(0.4)^4

Including the original 4m toss

Total distance travelled = 4m + ∑ drops+ ∑rebounds

= 4 + ∑ 4+4(0.4)+4(0.4)^2+.. + 4(0.4)^4

+∑4(0.4)+4(0.4)^2 + …….+4(0.4)^4

= 2∑4+4(0.4)+4(0.4)^2 + …….+4(0.4)^4

= 2 a(1-r^n)/(1-r)

= 2(4)(1–0.4^5)/(1–0.4) = 8(0.98976)/0.6

= 13.197 m

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