Question

a ball is vertically thrown upward with a velocity of 9.8m/s how high will the ball rise

Answer 1

but kinematics equation
v=0
u=9.8
a=9.8
now
${v}^{2} = {u}^{2} + 2 \times as \\ 0 = {(9.8)}^{2} + 2 \times ( - 9.8) \times s \\ s = \frac{ {(9.8)}^{2} }{2 \times 9.8} \\ s = 4.9m$

Answer 2

here is your answer hope this may help you