Question

a ball is vertically thrown upward with velocity 20 m/s. what will be its velocity after 1.5 sec of its motion?

Answer 1

Answer:

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at  

2

=20(2)+0.5(−10)(2)  

2

=20m

Thus, total distance for maximum height is 45 m

s=ut+0.5at  

2

 

45=0+0.5(10)(t  

′

)  

2

 

t  

′

=3s

Total time= 3+2= 5s

Explanation: