A ball is vertically thrown upwards with an initial velocity of 49m/s Calculate maximum height gained
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Answer:
the time is not given but i checked t the time is 5 sec!
Explanation:
Initial velocity of the ball (u) = 49m/s.
The velocity of the ball at maximum height (v) = 0.
g = 9.8m/s2
Let us considered the time taken is t to reach the maximum height H.
Consider a formula,
2gH = v2 – u2
2 × (- 9.8) × H = 0 – (49)2
– 19.6 H = – 2401
H = 122.5 m
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