Question

A ball mass 5 kg moving with speed 8 m/s collides head on with another stationary ball of mass 15 kg i if collision is perfectly inelastic then kinetic energy loss is

Answer 1

Hey dear,

◆ Answer-
120 J

◆ Explaination-
# Given-
m1 = 5 kg
u1 = 8 m/s
m2 = 15 kg
u2 = 0

# Solution-
According to law of conservation of momentum-
m1u1 + m2u2 = (m1+m2)v
5×8 + 15×0 = (5+15)v
v = 40/20
v = 2 m/s

Initial kinetic energy -
KEi = 1/2 m1u1^2 + 1/2 m2u2^2
KEi = 0.5×5×(8)^2 + 0.5×15×(0)^2
KEi = 160 J

Final kinetic energy -
KEf = 1/2 (m1+m2)v^2
KEf = 0.5 × (5+15) × 2^2
KEf = 40 J

Loss of kineic energy-
∆KE = KEi - KEf
∆KE = 160 - 40
∆KE = 120 J

Therefore, loss of kinetic energy in given inelastic collision is 120 J.

Hope this helps you...

Answer 2

Answer:

Explanation:

I hope..... Its help u...