a ball mass 50g thrown upwards. it rises to height 100m. at what height does kinetic energy be reduced to 70%?
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Total energy in the system = 50/1000×10×100 J = 50J
Let the required height be h.
When the Kinetic energy will be reduced to 70 percent .
Then, potential energy will be increased to 30 percent.
30/100×50 = 50/1000×10×(100-x)
30 =100-x
x =70.
Hence, required height = 70m
Let the required height be h.
When the Kinetic energy will be reduced to 70 percent .
Then, potential energy will be increased to 30 percent.
30/100×50 = 50/1000×10×(100-x)
30 =100-x
x =70.
Hence, required height = 70m
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