Question

A ball morning with velocity of 10ms hits a wall. It bounces back with the same
of 10 m/s. Caluculate the impulse from the wall ( mass of ball is 0.2 kg)
​

Answer 1

total impulse is 2mv , 2×0.2×10= impulse , impulse= 4 kgm/sec

Answer 2

Answer:

5 N

Explanation:

Assuming that the surface was frictionless and that the wall didn't absorb any momentum,

u = 0m/s ( at the point of contact with the wall)

v = 10m/s

m = 0.2kg

a = ( v-u )/t

= 10m/s^2

F = ma

F = ma= 0.2 * 10

F = ma= 0.2 * 10= 5 N

Thus, the impulse from the wall or force exerted is 5 N.

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