A ball moves in a circular path of 0.52 m diameter with a constant angular speed of 26 rev/min.
Its shadow performs simple harmonic motion on the wall behind it. Calculate:
(i) The velocity and acceleration of the shadow at the turning point;
(ii) The velocity and acceleration of the shadow at the equilibrium position;
and
(iii) The velocity at a point 8 cm away from the equilibrium position.
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Answer:
No 2
Explanation:
velocity and acceleration of the shadow at the equilibrium position and the velocity at a point 8 cm away from the equilibrium position
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