Physics, asked by syful0393, 5 hours ago

A ball moves in a circular path of 0.52 m diameter with a constant angular speed of 26 rev/min.
Its shadow performs simple harmonic motion on the wall behind it. Calculate:
(i) The velocity and acceleration of the shadow at the turning point;
(ii) The velocity and acceleration of the shadow at the equilibrium position;
and
(iii) The velocity at a point 8 cm away from the equilibrium position.

Answers

Answered by rumki940
0

Answer:

No 2

Explanation:

velocity and acceleration of the shadow at the equilibrium position and the velocity at a point 8 cm away from the equilibrium position

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