a ball moving with a momentum of 5kg m/s strikes against a wall at an angle of 45 degree and is reflected at the same angle. calculate the change in momentum (in magnitude).
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68
please see the image for solution. Components in y direction will cancel each other.
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53
hey there !!
=) As ball is moving with momentum 5kgm/s makes an angle 45° with horizontal to wall.
=) We know momentum is a vector quantity so resolving into components.
●------------------>5cos45
|
|
|
|
v
5sin45
◆ p1 = (5cos45)i - (5sin45)j
now F.B .D of ball after striking
5cos45 <------●
|
|
v
5sin45
◆ p2 = (-5cos45)i -(5 sin45)j
=) so change in momentum =( p2 - p1)
= -2× (5cos45)i
=) magnitude = 10cos45
= 10× 1/√2 = 5√2 kgm/s
=7.07kgm/s
________________________________
hope it will help u ^_^
=) As ball is moving with momentum 5kgm/s makes an angle 45° with horizontal to wall.
=) We know momentum is a vector quantity so resolving into components.
●------------------>5cos45
|
|
|
|
v
5sin45
◆ p1 = (5cos45)i - (5sin45)j
now F.B .D of ball after striking
5cos45 <------●
|
|
v
5sin45
◆ p2 = (-5cos45)i -(5 sin45)j
=) so change in momentum =( p2 - p1)
= -2× (5cos45)i
=) magnitude = 10cos45
= 10× 1/√2 = 5√2 kgm/s
=7.07kgm/s
________________________________
hope it will help u ^_^
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