Question

a ball moving with a speed of 9 m/s . strikes an identical ball. such that after the collision the direction of each balls makes an angle 30° with the original line of motion. find the speed of two balls after the collision the kinetic energy conserved in the collision processes​

Answer 1

Answer:

By momentum conservation in Y-direction.

mv

1

sin30−mv

2

2sin30=0

v

1

=v

2

In X direction,

mu

1

=mv

1

cos30+mv

2

cos30

m×3=2mv

1

×

2

3

v

1

=v

2

=

3

3

=

3

Answer 2

Answer:

5.2m/s

Explanation

In x direction

M1U1+M2U2=M1V1cos30+M2V2cos30

WKT U2=0

M1=M2

MU1=MV1cos30+MV2cos30

V1=V2

U1=2Vcos30

V=U/2cos30

V=9/2cos30

V=5.2m/s