Question

a ball moving with the initial velocity of 100 m/s north is given an acceleration of 10 m/s^2 south. what will be the velocity be after 6.0 seconds?

Answer 1

Given:-

initial velocity(u)=100m/s

acceleration(a)= -10m/s²(as it is in opposite direction)

time(t)=6s

To find:-

final velocity(v)

Solution:-

By v=u+at,we get------

v=100+(-10)6

v=100-60

v=40m/s

Thus,it's velocity after 6 seconds will be 40m/s.

Answer 2

Answer:

The velocity of the ball after 6 sec is 160 m/s north.

Explanation:

let, initial velocity be u

     final velocity be v

and acceleration be a

here, u =100 m/s

        a = 10m/s^2

         t = 6 sec

now, v = u + at

        v = 100 + 10(6)

        v = 160 m/s

therefore, velocity of the ball after 6 sec is 160 m/s north.