A ball moving with the momentum of p metre per second strikes against the wall at an angle of 45° and is reflected with same momentum at the same angle The change in momentum will be a} 2p cos45 b} 0 c}-2pcos45*
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Answer:Given,
P=5kgm/s
θ=45
0
from the figure given above, there is no change in perpendicular component and cancel each other.
The initial momentum along the x-axis,
P
i
=Pcosθ
The final momentum along the x-axis,
P
f
=−Pcosθ
So, change in momentum,
ΔP=P
f
−P
i
ΔP=−2Pcosθ
ΔP=−2×5×cos45
0
ΔP=−7.071kgm/s
Explanation:
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