Question

A ball moving with velocity i collides with a stationary wall and returns with a velocity J/2 .The coefficient of restitution for this collision is 1/K . Find K

Answer 1

Initial velocity of the ball  

u1 = i  

Initial velocity of the wall  

u2 = 0  

Final velocity of the ball  

v1 = j/ 2  

Final velocity of the wall  

u2 = 0  

e = (v2-v1)/(u1-u2)

e = (0-(1/2))/(1-0) = -0.5

Answer 2

Answer:

The Answer is K = 4

Explanation:

cos theta = 1/2 sin theta [The wall is frictionless]

= tan theta = 2

Coefficient of Restitution along line of force,

e = (1/2cos theta) ÷ (sin theta)

e = 1/2tan theta = 1/4

$\frac{1}{k} = \frac{1}{4} \\ \\ k = 4$