A ball moving with velocity20meter per second^-1step after travelling a distance of 10cm.Find its retardation
plz answer as soon as possible
Answers
Answered by
9
Answer:
v=20m/sec
distance=10cm
0.1m
from Newton 3 eq
v²=u²+2as
20²=2a×0.1
a=4000/2
a=2000m/sec
retardation is 2000m/sec
Answered by
0
Answer:
reetradation=change in velocity/time taken for change
reetradation=final velocity-initial velocity/time taken
retradation=0-20/0.005seconds
= -20/0.005
=4000m/sSq
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