A ball of 100 g mass is moved with 10 m/s, and decreases to 5 m/s in 5 seconds due to air friction, so force of friction due to air is
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Answer:
data
- m=100g=0.1kg
- vi=10m/s
- vf=5m/s
- f= ?
- t=5s
solution:
f=ma=m (vf-vi)/t
f=0.1×(5-10)/5
f=0.1 (-5)/5
☆f= -0.1N
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