Question

a ball of 2 kg is dropped from a height of 500m. What will be the speed with which the ball hit the ground
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Answer 1

Answer:

 100m/s

Explanation:

You can use the concept of conservation of total mechanical energy (neglecting the air resistance).

So, initially total mechanical energy = gravitational potential energy (kinetic energy is zero because initially there is no velocity).

Final total mechanical energy = kinetic energy (gravitational potential energy is zero because height has become zero).

So, initial mechanical energy = Final mechanical energy

(1/2)mv²=mgh

v(at height = 0) = √(2gh)

We can use this expression to find the maximum velocity or velocity just before touching the ground.

For this problem, v = √2×10×500 = 100m/s

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