Question

A ball of 2 kg moving with a speed of 25 m/s hits a stationary ball of mass 8 kg. After the collision these balls move together with a velocity of

Answer 1

$\huge {\underline{\pink{Given:-}}}$

• Mass ball ,m1 = 2kg

• Initial velocity ,u1 = 25m/s

• Mass of stationary ball ,m2 = 8kg

• Initial velocity ,u2 = 0m/s

• Final velocity of ball ,v1 = 0m/s (because it's hit the stationary ball)

$\huge {\underline{\green{To Find:-}}}$

• Combined velocity of balls v2

$\huge {\underline{\red{Solution:-}}}$

Using Conservation of momentum formula

• m1u1 + m2u2 = m1v1 + m2v2

Substitute the value we get

→ 2 × 25 + 8×0 = 2×0 + 8×v2

→ 50 + 0 = 0 + 8v2

→ 50 = 8v2

→ v2 = 50/8

→ v2 = 6.25 m/s

Therefore, the combined velocity of the ball is 6.25 m/s.

Answer 2

Answer:

✯ Given :-

• A ball of 2 kg moving with a speed of 25 m/s hits a stationary ball of mass 8 kg.

✯ To Find :-

• The combined velocity of the ball.

✯ Formula Used :-

❖ Conversation of momentum :

$\boxed{\bold{\large{\sf{✦\: m_1}\sf{u_1} + \sf{m_2}\sf{u_2} = \sf{m_1}\sf{v_1} + \sf{m_2}\sf{v_2\: ✦}}}}$

✯ Solution :-

⋆Given :

• m₁ = 2 kg
• u₁ = 25 m/s
• m₂ = 8 kg
• u₂ = 0 m/s
• v₁ = 0 m/s

➣ According to the question by using the formula we get,

⇒ (2)(25) + (8)(0) = (2)(0) + (8)(v₂)

⇒ 50 + 0 = 0 + 8v₂

⇒ 50 = 8v₂

⇒ v₂ = $\dfrac{50}{8}$

⇒ v₂ = 6.25 m/s

$\therefore$ The combined velocity of the ball is 6.25 m/s .