Question

A ball of 2 kg moving with a speed of 25 m/s hits a stationary ball of mass 8 kg. After the collision these balls move together with a velocity of

Answer 1

Here ..both the balls , after collision will move with same velocity .

The velocity of both the balls , after collision will be 5m/s.

Answer 2

According to collision theory,

$= > m1u1 + m1v1= m2u2 + m2v2$

Since , the second ball is at rest at initial state, and after collision both will have same velocity.

$= > 2 \times 25+ 2v = 0 + 8v$

$= > 50 + 2v = 8v$

$= > 8v - 2v = 50$

$= > 6v = 50$

$= > v = \frac{50}{6} = 8.34m {s}^{ - 1}$

Hope this answer helps you ^_^ !