a ball of 20 g hits a wall at an angle of 45° with velocity of 15 m/s. if ball rebound at 90° to the direction of incidence the cal impulse received by ball
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Answer:
m=20g=0.02kg,
v=15m/s
Impulse is given by momentum change =m.Δv
=0.02(−15−15)sin45
=0.42kg.m/s
Explanation:
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