Question

A ball of 500 gram hits a wall with a velocity 10 metre per second such that it makes an angle 60 degree with the normal it bounces back with the same speed making an angle of 60 degree with the normal determine the change in momentum.​

Answer 1

Answer:

Impulse = Change in momentum

ΔP=P

f

−P

i

=m(v

f

−v

i

)=0.1(30−(−20))=0.1×50=5Ns

Answer 2

Answer:

mass = 500gm = 0.5kg

velocity = 10m/s

change in momentum (∆P) = 5√3kgm/s

Explanation:

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