Question

A ball of 5kg is dropped from a tower of height 6 meters. What is its kinetic energy halfway through? (Use g = 9.8 m/s2)

Answer 1

Answer:

it certain height PE energy of the body is...

PE = mgh

PE=5×10×6

PE=300

now it halfway height become half

PE=mgh

PE=5×10×3

PE=150

Now according to law of conservation of energy lost potential energy converted into kinetic energy (in this case).

so 300-150=150

150 is the required answer.......

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