Question

A ball of a mass 100g falls from a height of 3m unto a horizontal surface and bounce to the height of 12m calculate the change in the momentum of the ball when it strikes the surface.

Answer 1

Answer:

Do you mean bounce to 1.2 meter? I hope.

(1/2) m v^2 at floor = m g h at top

so

v = sqrt (2 g h) (but you knew that)

so

v down = sqrt (2*9.8*3)

v up = sqrt(2*9.8*1.2)

opposite signs so add

change in momentum = m * [ sqrt (2*9.8*3) + sqrt(2*9.8*1.2) ]

Explanation:

mark me brainlist