A ball of an unknown mass is thrown upward at a speed of 10 m s-1, calculate maximum height reached by ball if acceleration due to gravity is assumed to be 10 m s-1. 5 m
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5 is the correct ans.
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Arinan:
kon bhaiya aap
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v=u+at
0=10+(-10)(t)
-10=-10t
-10/-10=t
1=t
s=ut+1/2at^2
s=10(1)+1/2(-10)(1)^2
s=10+(-5)
s=5m
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