Question

A ball of diameter 13 centimetres is floating in a pond if the top of the ball is 4 cm above the surface of the pond then the radius of the circle formed by the contact of water surface with the ball is...
A) 13 cm
B)6.5 cm
C) 6 cm
D)9 cm

Answer 1

Answer:

hey mate your answer is

Step-by-step explanation:

a ball of diameter =13

diameter formula=2*r

=2*13=26r

2.a ball above 4cm on the surface=26/4=6.5cm

mark as brilliant answer .

Answer 2

Answer:

The correct option is C.

Step-by-step explanation:

The diameter of the ball is 13 cm. So, the radius of the ball is half of its diameter.

r = 6.5 cm

It is given that the ball is floating in a pond if the top of the ball is 4 cm above the surface of the pond. So, the distance between water surface to the center is

6.5 - 4 = 2.5

Let the radius of the circle formed by the contact of water surface with the ball is x.

Using Pythagoras theorem:

$hypotenuse^2=base^2+perpendicular^2$

$(6.5)^2=(x)^2+(2.5)^2$

$(6.5)^2-(2.5)^2=(x)^2$

$36=(x)^2$

Taking square root on both sides.

$x=6$

Therefore, the correct option is C.