Question

A ball of k.E is 68J projected at an angle 60 to horizontal K.E of ball at highest point of its flight will be​

Answer 1

Answer:

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Answer 2

The kinetic energy of the particle will be 1/2E.

Explanation:

We have the values given as under

Let us assume the initial velocity of the particle be "v"

Kinetic energy = 1/2mV² = E-→ 1

Particle velocity at the highest point it reaches is = V cos 45

The particle's kinetic energy at highest point is = 1/2m (v cos 45)²

= 1/2 (mv²) (1/2) [from equation 1 we can conclude}

= 1/2E

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