Question

A ball of mass 0.01kg moves with a velocity of 100m/sec .how much uniform force will stop it in 10 sec​

Answer 1

Given:

• Mass ,m = 0.01 kg

• Initial velocity,u = 100 m/s

• Final velocity,v = 0 ( Rest )

• Time taken, t = 10 s

To be calculated:

How much uniform force will stop the ball ?

Formula used:

• Acceleration = v - u / t

• Force = m × a

Solution:

We know that ,

Acceleration = v - u / t

★Substituting the values in the above formula,we get

Acceleration = 0 - 100 / 10

= -100 / 10

= - 10 m/s² ( Negative acceleration or retardation)

Now,

Force = mass × acceleration

★ Putting the values of mass and acceleration, we get

Force = 0.01 kg × ( -10 m/s² )

= 1/100 × -10

= - 1 / 10

= - 0.1 kg.m/s² or 0.1 N

Answer 2

Answer:

Explanation:

Given :-

Mass, m = 0.01 kg

Initial velocity, u = 100 m/s

Final velocity, v = 0 (As stops)

Time taken, t = 10 seconds

To Calculate :-

Force, f = ??

Formula to be used :-

Acceleration, a = v - u/t

Force = Mass × Acceleration

Solution :-

Putting all the values, we get

a = v - u/t

⇒ a = 0 - 100/10

⇒ a = - 100/10

⇒ a = - 10 m/s²

Now, Force, f

Force = Mass × Acceleration

⇒ Force = 0.01 × (- 10)

⇒ Force = 0.1 Newton.

Hence, the force acquired is 0.1 Newton.