A ball of mass 0.1 kg moving at 10 m s–1 is deflected by a wall at the same speed in the direction shown. What is the magnitude of the change in momentum of the ball?
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initial velocity( U^) = -10cos45° I -10sin45°j
final velocity = 10cos45° i -10sin45° j
now,
change in momentum =final momentum - initial momentum
=m( 10cos45° i -10sin45 j ) -m( -10cos45° I -10sin45° j )
=m{ 20cos45° I }
=0.1 x 20 x 1/√2 i
=√2 i kg.m/s
final velocity = 10cos45° i -10sin45° j
now,
change in momentum =final momentum - initial momentum
=m( 10cos45° i -10sin45 j ) -m( -10cos45° I -10sin45° j )
=m{ 20cos45° I }
=0.1 x 20 x 1/√2 i
=√2 i kg.m/s
Akasx:
250 is the answer.
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