Question

A ball of mass 0.1 kg strikes a
wall normally with a speed of
30 m/s and rebounds with a speed
of 20 m/s. The magnitude of
change in momentum of the ball is
✓
​

Answer 1

P=mu

=0.1×30

=3

P=mv

=0.1×-20

=-5

change of momentum=mv-mu

=3-(-2)

=5kgm/s

Answer 2

P=mu

=0.1×30

=3

P=mv

=0.1×-20

=-2

change of momentum=mv-mu

=-2-3

=-5

=-5kgm/s

So force(f)=5kgm/s

Please have a great day and please mark my answer as brainliest.