Question

A ball of mass 0.10 kg is dropped from a height of 18 m. Its momentum when it strikes the ground is?​

Answer 1

Answer:

when it strike

Explanation:

initally it's velocity is zero u=0,

using formula

${v}^{2} = {u}^{2} + 2gh$

${v}^{2} = {0}^{2} - 2 \times 10 \times ( - 18)$

v^2=360

v=

$\sqrt{360}$

=

$6 \sqrt{10}$

momentum is MV=0.10x6root10