Physics, asked by nehakumari160699, 10 months ago

A ball of mass 0.10 kg is dropped from a height of 18 m. Its momentum when it strikes the ground is? (2.4 kg m/s, 1.9 kg m/s, 1.5 kg m/s, 3.8 kg m/s).​

Answers

Answered by kishant573
1

Explanation:

when it is dropped it velocity is zero

u=0

using formula v^2=u^2-2gh

v^2=0^2-2x10x(-18)

v^2=360

v=6root10

Momentum=0.1x6√10

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