A ball of mass 0.10 kg is dropped from a height of 18 m. Its momentum when it strikes the ground is? (2.4 kg m/s, 1.9 kg m/s, 1.5 kg m/s, 3.8 kg m/s).
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Explanation:
when it is dropped it velocity is zero
u=0
using formula v^2=u^2-2gh
v^2=0^2-2x10x(-18)
v^2=360
v=6root10
Momentum=0.1x6√10
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