Question

A ball of mass 0.15 kg is dropped from a height 10m strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is (g=10m/s²) nearly:
1)O kg m/s 2) 4. 2 kg m/s 3) 2.1 kg m/s​

Answer 1

Given info : A ball of mass 0.15 kg is dropped from a height 10m strikes the ground and rebounds to the same height.

To find : the magnitude of impulse imparted to the ball is ..

solution : impulse is the change in linear momentum of a particle.

so we should find the velocity of ball at first.

using formula, v² = u² + 2as

here, u = 0 m/s , a = g = 10 m/s and s = 10 m

so, v₁² = 2 × 10 × 10 = 200

⇒ v₁ = 10√2 m/s

but the ball is dropped so the velocity would be negative and that is v₁ = -10√2 m/s

again, ball rebounds to the same height.

so, velocity of ball needed to reach the height h = 10m, v₂ = √(2gh) = 10√2m/s [ it will be positive because motion of ball is upward. ]

now the impulse = change in linear momentum

                            = final linear momentum - initial linear momentum

                            = mv₁ - mv₂

                            = 0.15 × 10√2 - 0.15 × -10√2

                            = 0.15 × 20√2 ≈ 4.2

therefore the magnitude of impulse imparted to the ball is nearly 4.2 kgm/s.

Answer 2

Step-by-step explanation:

Hope this may help you

thank you