Question

A ball of mass 0.16kg is moving forwards at a speed of 0.50m/s. A second ball of mass 0.10kg is stationary. The first ball strikes the second ball. The second ball moves forwards at a speed of 0.50m/s. What is the speed of the first ball after the collision

Answer 1

Answer:

Final velocity of $M_{1}$ = 0.18 m/s

Explanation:

The law of conservation of momentum states that In a collision of an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

   ⇒Momentum is given by the equation: Mass x Velocity

• Mass of $M_{1}$  = 0.16 kg

• Initial velocity of $M_{1}$ = 0.50 m/s

• Initial momentum of $M_{1}$ = $(0.16)(0.50)$ = 0.08 kgm/s

• Mass of $M_{2}$ = 0.10 kg

• Initial velocity of $M_{2}$ = 0 m/s

• Initial momentum of $M_{2}$ = $(0.10)(0)$ = 0 kgm/s

⇒⇒ Total momentum before the collision = $(0.08)(0)$ = 0.08 kgm/s

• Final velocity of $M_{2}$ = 0.50 m/s

• Final momentum of $M_{2}$ = $(0.10)(0.50)$ = 0.05

kgm/s

Final momentum of $M_{1}$ = Total momentum - Final Momentum of $M_{2}$

                                    $(0.08) - (0.05)$ = 0.03 kgm/s

Then final velocity of $M_{1}$ = Final momentum of

                                        $\frac{0.03}{0.16}$ = 0.18 m/s