A ball of mass 0.1kg is thrown against a wall.It Strikes the wall normally with a velocity of 30 m/s and it rebonds with a velocity of 20m/s. Calculate the impulse of the force entered by the wall on the ball?
Answers
Given :
- Mass of the ball = 0.1 kg.
- Initial velocity = 30 m/s.
- Final Velocity = 20 m/s.
To find :
Impulse imparted on the ball.
Solution :
We know the formula for impulse i.e,
Where :-
- I = Impulse
- m = Mass of the body.
- v = Final Velocity
- u = Initial Velocity.
Now using the above equation and substituting the values in it, we get :
Hence the Impulse imparted by the ball is -1 kg m/s.
Additional Information :-
Definition of Impulse :
Impulsive force or impulse is a application of a large amount of force , acting on a body for a short time interval.
Impulse = Force × Time
We know that Force is the Product of Mass and Acceleration , so by substituting it in the equation , we get :
==> Impulse = m a t
We also know that Acceleration is the Rate of change in velocity.
By substituting it in the equation , we get :
==> Impulse = m × (v - u)/t × t
==> Impulse = m(v - u).
∴ Impulse = m(v - u)
Hence Derived !!
Dimension Formula for Impulse :
Impulse = M¹L¹T-¹
We know the formula for impulse i.e,
Where :-
I = Impulse
m = Mass of the body.
v = Final Velocity
u = Initial Velocity.
Now using the above equation and substituting the values in it, we get :
Hence the Impulse imparted by the ball is -1 kg m/s.
Additional Information :-
Definition of Impulse :
Impulsive force or impulse is a application of a large amount of force , acting on a body for a short time interval.
Impulse = Force × Time
We know that Force is the Product of Mass and Acceleration , so by substituting it in the equation , we get :
==> Impulse = m a t
We also know that Acceleration is the Rate of change in velocity.
By substituting it in the equation , we get :
==> Impulse = m × (v - u)/t × t
==> Impulse = m(v - u).