A ball of mass 0.2 kg falls through air with an acceleration of 6 ms^-2. Calculate the air drag on the ball.
Answers
Answered by
14
F1=ma
F=0.2×6
1.2N(it's the force by which ball is coming down)
F2=ma
F=0.2×9.8
1.96N(the force apposing the ball)
Now drag will be
F2 - F1
1.96N-1.2N =.76N
7.6N. is the answer
F=0.2×6
1.2N(it's the force by which ball is coming down)
F2=ma
F=0.2×9.8
1.96N(the force apposing the ball)
Now drag will be
F2 - F1
1.96N-1.2N =.76N
7.6N. is the answer
Amit0503:
the answer is 0.76 N. That's it.
Answered by
0
Answer:
thanks for the answers maths aryabarta
Similar questions
Social Sciences,
7 months ago
World Languages,
7 months ago
Social Sciences,
7 months ago
Physics,
1 year ago
Math,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago