Question

A ball of mass 0.2 kg falls through the air with an acceleration of 6m/s .Calculate the air drag of the ball

Answer 1

heya !! ☺☺☺
F1=ma

F=0.2×6

1.2N(it's the force by which ball is coming down)

F2=ma

F=0.2×9.8

1.96N(the force apposing the ball)

Now drag will be

F2 - F1

1.96N-1.2N =.76N....
I hope it help's u....✌✌✌

Answer 2

HEY BUDDY..!!!

HERE'S THE ANSWER..

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♠️ First I want to make this concept clear that if a body is allowed to fall free the mass of body remains constant and Acceleration is also constant which is know as Acceleration due to gravity ( g ) , as [ g = 9.8 m / s^2 or 10 m / s^2 ]

▶️ First we'll find the force by which ball of mass 0.2 kg is falling , F = m × g

=> Force = mass × Acceleration ( g )

=> F = 0.2 × 10

=> F = 2 N .


⏺️ Now force by which mass if falling and drag is applied.

=> F = m × a

=> F = 0.2 × 6

=> F = 1.2 N


♠️ To find net net force which is drag in this case .

=> Force due to free fall - force with applied drag

=> Drag = 2 - 1.2

=> Drag = 0.8 N



HOPE HELPED..

JAI HIND..

:-)