Question

a ball of mass 0.2 kg is allowed to fall from a height of 5m and after hiting the floor bounces back to a height of 4m determine the impulse of ball is subjected to if the time of impart is 0.1 estimate the force experienced by the ball.

Do not post irrelevant answers. Please help me with this question ​

Answer 1

Explanation:

Velocity before strice = u downward

Velocity after strike = V upward

u=root2gS1=root2×5×5=5root2m/s    g = 5 taking 

V=root2gS2=root2×5×4=root40m/s=2root10

change in momentum = impulse

mu-(mv)=F×t

F= 1×2root5+2root10/t

F= 2root 5(1+root2)/t

F= 2root5(1+1.41)/0.1

F=2×2.236(2.41)/0.1

F= 2×5.388/0.1

F=10.777/0.1

F=107.77N