Question

A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand if the hand moves 0.2 applying the force and the ball goes up to 2 metre height further find the magnitude of force

Answer 1

Answer:

22N

Explanation:

Let the ball start moving with velocity u and it reaches up to a maximum height H.

From H = u^2/2g

u=√2gH =√2*10ms^-2*2m

=2√10 ms^-1

This velocity is supplied to the ball by the hand and initially the hand was at reat, it acquires this velocity is distance of 0.2m.

Therefore,

a=u^2/2S = (2√10 ms^-1)^2/2*0.2m

=100ms^-2

So upward force on the ball is

F= m(g+a) =0.2kg(10ms^-2+100ms^-2)

=22N

Answer 2

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↠ A ball of mass 0.2 kg is thrown vertically

by applying a force by hand.

↠ hand moves 0.2 m while applying the

force and the ball goes 2 m heights

↠ g = 10 m/s²

$\huge\pink{\underline{\boxed{\mathbb{Given}}}}$]

↠ Mass of ball = 0.2 kg.

↠ Total height = 0.2 + 2 = 2.2 m

↠ Total displacement = 0.2 m

$\huge\pink{\underline{\boxed{\mathbb{To Find}}}}$]

The magnitude of the force.

SoLuTioN :--

↠ Work done = Difference in potential difference.

↠ FS = MGH.

↠ F = MGH / S

↠ F = 0.2 X 10 X 2.2 / 0.2

↠ F = 22 N