Question

A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 m while applying the force and the ball goes upto 2 m height further, find the magnitude of the force. (Consider g = 10m/s^2`).

Answer 1

EXPLANATION.

=> A ball of mass 0.2 kg is thrown vertically

by applying a force by hand.

=> hand moves 0.2 m while applying the

force and the ball goes 2 m heights

=> g = 10 m/s² [ Given ]

=> Mass of ball = 0.2 kg.

=> Total height = 0.2 + 2 = 2.2 m

=> Total displacement = 0.2 m

=> Work done = Difference in potential difference.

=> FS = MGH.

=> F = MGH / S

=> F = 0.2 X 10 X 2.2 / 0.2

=> F = 22 N

Answer 2

$\huge\bf{\underline{\underline{\gray{GIVEN:-}}}}$

• Mass of a ball is 0.2 kg.

• A ball is thrown vertically upwards by applying a force by hand .

• If the hand moves 0.2 m while applying the force .

• And the ball goes upto 2 m height further .

$\huge\bf{\underline{\underline{\gray{TO\:FIND:-}}}}$

• The magnitude of the force .

$\huge\bf{\underline{\underline{\gray{SOLUTION:-}}}}$

According to the question,

• $\bf\red{m}$ = 0.2 kg

• $\bf\red{Total\:height(h)}$ = 0.2 + 2 = 2.2 m

We know that,

$\purple\bigstar\:\bf{\red{\overbrace{\underbrace{\orange{Work\:done\:=\:Difference\:in\:potential\:energy\:}}}}}$

$\rm{{\orange{:\implies}}\:Work\:done\:=\:\triangle{U}\:}$

$\bf{{\green{:\implies}}\:F\:.\:S\:=\:mgh\:}$

Where,

• $\bf\red{F}$ = Force

• $\bf\red{S}$ = The distance for ehich the force is applied by hand .

$\rm{{\orange{:\implies}}\:F\:=\:\dfrac{mgh}{S}\:}$

$\rm{{\green{:\implies}}\:F\:=\:\dfrac{0.2\times{10}\times{2.2}}{0.2}\:}$

$\rm{{\orange{:\implies}}\:F\:=\:\dfrac{4.4}{0.2}\:}$

$\bf{{\green{:\implies}}\blue{\:F\:=\:22\:N}\:}$

$\huge\red\therefore$ The magnitude of the force is "22 N" .