A ball of mass 0.25 kg is moving horizontally with uniform velocity of 25 m/s. Calculate the kinetic energy possessed by the ball.
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Answers
Answered by
10
1/2 mv^2=1/2×0.25×25×25...=78.125J
Answered by
38
Hi there!
Here,
Mass, m = 0.25 kg
Final velocity, v = 25 m/s
K.E. = 1/2 × mv²
= 0.5(m)v²
= 0.5(0.25)(25)²
= 78. 125 Joules (J)
[ Thank you! for asking the question. ]
Hope it helps!
Here,
Mass, m = 0.25 kg
Final velocity, v = 25 m/s
K.E. = 1/2 × mv²
= 0.5(m)v²
= 0.5(0.25)(25)²
= 78. 125 Joules (J)
[ Thank you! for asking the question. ]
Hope it helps!
thnks
welcome brother!
I guess i did the same
awzm probex
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