Question

A ball of mass 0.25 kg moving horizontally with a velocity 20 ms 1is struck by a bat. The duration of contact is 10-2s. After leaving the bat, the ball moves at a speed of 40 ms1in a direction opposite to the original direction of motion. Calculate the average force exerted by the bat.

Answer 1

Answer:

A ball of mass 0.25 kg moving horizontally with a velocity 20 ms-1 is struck by a bat. The duration of contact is 10-2s. After leaving the bat, the ball moves at a speed of 40 ms-1 in a direction opposite to the original direction of motion.

Explanation:

Given: v = 10 ms-1

u = - 10 ms-1

m = 0.25kg

Δ t = 0.01s

Change in momentum, Δ P = mv - mu Δ P = 0.25 (10) - 0.25 ( - 10) = 5 kgms-1 Force acting on bat, ... A cricket ball of mass 0.25kg with speed 10m/s collides with a bat and ... If its time of contact with wall is t, then find force exerted by ball on the wall.