A ball of mass 0.25kg moves on frictionless horizontal floor and hits a vertical wall with 5m/s. the ball rebounds with 40m/s. if the ball was in contact with the wall for 0.150 seconds ,the average force that acts on the ball is
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average force × time = change in momentum
average force = 0.25 × ( 40 + 5 ) / 0.15 = 75 N
average force = 0.25 × ( 40 + 5 ) / 0.15 = 75 N
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