Question

A ball of mass 0.25kg moving at 2m/s collides head on with a ball of 0.10kg that in stationary. If the first ball
comes to rest after the impact, then the speed acquired by the other ball is​

Answer 1

Answer:

Step-by-step explanation:

For ball A:

p = m * v

p = 0.25 * 1.2

p = 0.3 kg m s-1

Let's call this value pA.

For ball B:

p = m *v

p = 0.25 * 0

p = 0.

Let's call this value pB.

So now we can work out the total momentum before the collision:

ptotal = pA + pB = 0.3 + 0 = 0.3 kg m s-1.

Answer 2

Answer:

Step-by-step explanation:

For ball A:

P= NV

p=0.25*1.2

p=0.3 kg m/s

For ball B:

P=mv

p=0.25*0

p=0

P total=0.3+0

p=0.3 kg m/s