Question

A ball of mass 0.2kg is thrown normally against a wall with a speed of 20m/s and it rebound at a speed of 15m/s then the impulse by the ball on the wall is

Answer 1

hello dear... ☺
get your answer here....


so, we know,
impulse (J) =change in momentum
which is =m(v2-v1)
=0.2(15-20)
=–1n-s

here my friend
you have to understand that the –ve sign means that a force of 1N is acting in opposite direction of the motion of ball⚽


hope it's helpful ☺