Question

A ball of mass 0.2kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2m while applying the force and the ball goes upto 2m height further, find the magnitude of the force. Consider g=10m/s

Answer 1

Answer:

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Explanation:

A ball of mass 0.2 kg is thrown vertically

by applying a force by hand.

=> hand moves 0.2 m while applying the

force and the ball goes 2 m heights

=> g = 10 m/s² [ Given ]

=> Mass of ball = 0.2 kg.

=> Total height = 0.2 + 2 = 2.2 m

=> Total displacement = 0.2 m

=> Work done = Difference in potential difference.

=> FS = MGH.

=> F = MGH / S

=> F = 0.2 X 10 X 2.2 / 0.2

=> F = 22 N

Answer 2

Mass ,m=0.2kg

Total height, h=0.2+2=2.2m

Work done =Difference in potential energy.

F.S=mgh where S is the distance for which the force is applied by hand,

S=0.2m

$\sf \: F = \frac{mgh}{s} = \frac{0.2 \times 10 \times 2.2}{0.2} \\ \sf \: F= 22n$